What will be output of the following c code?

#include "stdio.h"
#include "string.h"
void main()
{
char c='\08';
printf("%d",c);
}

Choose the correct answer:

A) 8

B) 9

C) 10

D) Compile error

Detailed Explanation

In c any character is starting with character ‘\’ represents octal number in character. As we know octal digits are: 0, 1, 2, 3, 4, 5, 6, and 7. So 8 is not an octal digit. Hence ‘\08’ is invalid octal character constant.

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What will be output of the following c code?#include "stdio.h"#include "string.h"void main() { char c='\08'; printf("%d",c); }

Choose the correct answer:

Detailed Explanation

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What will be output of the following c code?

#include "stdio.h"
#include "string.h"
void main()
{
char c='\08';
printf("%d",c);
}