What will be output of following c code?

#include<stdio.h>

#define p(a,b) a##b

#define call(x) #x

int main(){

    do{

         int i=15,j=3;

         printf("%d",p(i-+,+j));

    }

    while(*(call(625)+3));

    return 0;

}

 

First iteration:

p(i-+,+j)

=i-++j   // a##b

=i - ++j

=15 – 4

= 11

While condition is : *(call(625)+ 3)

= *(“625” + 3)

Note: # preprocessor operator convert the operand into the string.

=*(It will return the memory address of character ‘\0’)

= ‘\0’

= 0  //ASCII value of character null character

Since loop condition is false so program control will come out of the for loop