Web Development
TypeScript
Subjective
Oct 04, 2025
How do you create a type that validates function argument relationships?
Detailed Explanation
Use conditional types with infer to extract parameter types and validate relationships between arguments.
Basic Parameter Validation:
type ValidateArgs = T extends (...args: infer P) => any ? P : never;
type FirstArg = T extends (first: infer F, ...rest: any[]) => any ? F : never;
type SecondArg = T extends (first: any, second: infer S, ...rest: any[]) => any ? S : never;
// Ensure second argument extends first
type RelatedArgs = U extends T ? [T, U] : never;
function processRelated(first: T, second: U): void {
// Implementation
}
Advanced Validation:
type ValidateFunctionArgs = F extends (...args: infer P) => any
? P extends [infer A, infer B]
? B extends A
? F
: never
: F
: never;
// Usage
type ValidFunction = ValidateFunctionArgs<(base: string, extended: string) => void>; // OK
type InvalidFunction = ValidateFunctionArgs<(base: string, extended: number) => void>; // never
Benefits:
• Compile-time argument validation
• Ensures type relationships between parameters
• Prevents invalid function signatures
• Provides excellent type safety.
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